Here is something I created.
Let $\varphi$ denote Euler’s totient function. Evaluate the limit
$$\ell = \lim_{n \rightarrow +\infty} \frac{1}{n^2} \sum_{k=1}^{n} \sin \left (\frac{\pi k}{n} \right) \varphi(k)$$
Search found 597 matches
- Wed Apr 19, 2017 11:34 am
- Forum: Real Analysis
- Topic: A limit with Euler's totient function
- Replies: 1
- Views: 5616
- Tue Apr 11, 2017 7:30 pm
- Forum: Real Analysis
- Topic: A zeta limit
- Replies: 2
- Views: 6725
A zeta limit
Let us denote with $\zeta$ the Riemann zeta function defined as $\zeta(0)=-\frac{1}{2}$. Let us also denote with $\zeta^{(n)}$ the $n$-th derivative of zeta. Evaluate the limit
$$\ell=\lim_{n \rightarrow +\infty} \frac{\zeta^{(n)}(0)}{n!}$$
$$\ell=\lim_{n \rightarrow +\infty} \frac{\zeta^{(n)}(0)}{n!}$$
- Wed Apr 05, 2017 7:05 pm
- Forum: Real Analysis
- Topic: Existence ?
- Replies: 2
- Views: 3289
Re: Existence ?
We show that the series $\sum_{n=1}^\infty\,f(n)/n^2$ diverges for any bijective from $\mathbb{N}$ to $\mathbb{N}$. To see this, since $f$ is a permutation of $\mathbb{N}$, it follows that $$f(1) + f(2) + \cdots + f(n) \geq 1 + 2 + \cdots + n = \frac{n(n+1)}{2}.$$ Thus, by Abel's summation formula,...
- Sun Mar 26, 2017 2:23 pm
- Forum: Archives
- Topic: A collection of problems in Analysis
- Replies: 4
- Views: 10006
A collection of problems in Analysis
Greetings, I have assembled here some problems in Analysis that are quite entertaining and some of them are quite challenging. The following booklet contains problems from $4$ main branches of Mathematical Analysis: Real and Complex Analysis Multivariable Calculus General Topology Integrals and Seri...
- Sat Feb 11, 2017 10:46 pm
- Forum: General Mathematics
- Topic: The number is an integer
- Replies: 0
- Views: 4780
The number is an integer
Prove that the number
$$\mathcal{N}=(2+\sqrt{3})^n +(2-\sqrt{3})^n$$
is an integer.
$$\mathcal{N}=(2+\sqrt{3})^n +(2-\sqrt{3})^n$$
is an integer.
- Fri Jan 06, 2017 10:09 pm
- Forum: General Mathematics
- Topic: n-th root of a continued fraction of Lucas numbers
- Replies: 0
- Views: 3028
n-th root of a continued fraction of Lucas numbers
Let us denote the $n$ -th Lucas number as $L_n$. It is known that $L_0=2$ , $L_1=1$ as well as
$$L_{n+2}=L_{n+1} + L_{n} \quad \text{forall} \; n \geq 0$$
Calculate the value of
$$\mathcal{R}=\sqrt[n]{L_{2n} - \frac{1}{L_{2n}- \dfrac{1}{L_{2n}-\ddots}}}$$
I don't have a solution.
$$L_{n+2}=L_{n+1} + L_{n} \quad \text{forall} \; n \geq 0$$
Calculate the value of
$$\mathcal{R}=\sqrt[n]{L_{2n} - \frac{1}{L_{2n}- \dfrac{1}{L_{2n}-\ddots}}}$$
I don't have a solution.
- Sun Dec 04, 2016 4:26 pm
- Forum: Multivariate Calculus
- Topic: On the calculation of a surface integral
- Replies: 0
- Views: 3007
On the calculation of a surface integral
Let
$$\mathbb{S}=\left\{ (x, y, z) \in \mathbb{R}^3 \big| x^2 + y^2 +z^2 \leq 1 \right\}$$
Evaluate the surface integral:
$$\mathfrak{S}=\iiint \limits_{\mathbb{S}} \cosh (x + y + z ) \, {\rm d} (x, y, z)$$
$$\mathbb{S}=\left\{ (x, y, z) \in \mathbb{R}^3 \big| x^2 + y^2 +z^2 \leq 1 \right\}$$
Evaluate the surface integral:
$$\mathfrak{S}=\iiint \limits_{\mathbb{S}} \cosh (x + y + z ) \, {\rm d} (x, y, z)$$
- Tue Nov 29, 2016 12:42 pm
- Forum: General Mathematics
- Topic: The number is rational
- Replies: 1
- Views: 5415
The number is rational
Let $n \in \mathbb{N}$ . Prove that the number
$$\mathfrak{n}=\sqrt{\underbrace{1111\cdots11}_{2n} - \underbrace{2222\cdots22}_{n}}$$
is rational.
$$\mathfrak{n}=\sqrt{\underbrace{1111\cdots11}_{2n} - \underbrace{2222\cdots22}_{n}}$$
is rational.
- Tue Nov 29, 2016 12:40 pm
- Forum: General Mathematics
- Topic: Inequality
- Replies: 0
- Views: 2942
Inequality
Let $a,b, c$ be positive real numbers. Prove that:
$$\sqrt{\frac{2a}{a+b}} +\sqrt{\frac{2b}{b+c}} + \sqrt{\frac{2c}{c+a}} \leq 3$$
(V. Cirtoaje)
$$\sqrt{\frac{2a}{a+b}} +\sqrt{\frac{2b}{b+c}} + \sqrt{\frac{2c}{c+a}} \leq 3$$
(V. Cirtoaje)
- Sun Nov 20, 2016 12:19 pm
- Forum: Algebraic Structures
- Topic: The group is abelian
- Replies: 1
- Views: 5989
The group is abelian
Here is an exercise that caught my attention the other day. Let $\mathcal{G}$ be a finite group such that $\left ( \left | \mathcal{G} \right | , 3 \right ) =1$. If for the elements $a, \beta \in \mathcal{G}$ holds that: $$\left ( a \beta \right )^3 = a^3 \beta^3$$ then prove that $\mathcal{G}$ is ...