A limit

Real Analysis
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Tolaso J Kos
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A limit

#1

Post by Tolaso J Kos »

Prove that:

$$\lim_{n\to +\infty}\left[\sum_{i=1}^{n}\frac{1}{\sqrt{i}} - 2\sqrt{n}\right]=\zeta \left( \frac{1}{2}\right)$$

where $\zeta$ is Riemann's zeta function.
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Riemann
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Re: A limit

#2

Post by Riemann »

$\displaystyle \sum_{n=1}^{\infty}\frac{1}{n^s}= \prod_{p \; \text{prime}}\frac{1}{1-p^{-s}}$
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